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Question

To travel through the same distance in two different media, a light ray of certain frequency takes different times which are in the ratio 3: 5, the relative refractive index is :

A
5/3
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B
3/2
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C
5/2
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D
7/5
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Solution

The correct option is A 5/3
Speed of light in medium is
v=cμ
So, t=DV=DμC [Let D is the distance travelled]
So, t1t2=Dμ1C×CDμ2
μ1μ2=t1t2
= 35 or μ2=53μ1
So, relative refractive index is 53

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