To travel through the same distance in two different media, a light ray of certain frequency takes different times which are in the ratio 3: 5, the relative refractive index is :
A
5/3
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B
3/2
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C
5/2
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D
7/5
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Solution
The correct option is A 5/3 Speed of light in medium is v=cμ So, t=DV=DμC [Let D is the distance travelled] So, t1t2=Dμ1C×CDμ2 ⇒μ1μ2=t1t2 = 35 or μ2=53μ1 So, relative refractive index is 53