Question

To tune a parallel resonant circuit to a higher frequency, the capacitance should be

• A. Increased
• B. Decreased
• C. Left alone
• D. Replaced with inductance

Answer 1

The correct option is B Decreased

Resonant frequency =$\frac{1}{\left[\right(2\pi )\times \sqrt{CL}]}$

Therefore increasing the value C with the value of L held constant decreases the resonant frequency.

Hence, To tune a parallel resonant circuit to a higher frequency, the capacitance should be decreased.