To warm ships for underwater rocks, a light house throws a red coloured light over a sector of 80 $^{o}$ angle to a distance of 16.5 km. Find the area of the sea over which the ships area warmed.

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Solution

$r = 16.5$ $k m$
$θ = 80$
Therefore, area of the sea over which the ships are warmed
$= \frac{θ}{360} \times π r^{2} = \frac{80}{360} \times 3.14 \times 16.5 \times 16.5 = 189.97$ $k m^{2}$

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To warm ships for underwater rocks, a light house throws a red coloured light over a sector of 80o angle to a distance of 16.5 km. Find the area of the sea over which the ships area warmed.

r=16.5 kmθ=80Therefore, area of the sea over which the ships are warmed=θ360×πr2=80360×3.14×16.5×16.5=189.97 km2

To warm ships for underwater rocks, a light house throws a red coloured light over a sector of 80 $^{o}$ angle to a distance of 16.5 km. Find the area of the sea over which the ships area warmed.

$r = 16.5$ $k m$
$θ = 80$
Therefore, area of the sea over which the ships are warmed
$= \frac{θ}{360} \times π r^{2} = \frac{80}{360} \times 3.14 \times 16.5 \times 16.5 = 189.97$ $k m^{2}$