Question

To what effect potential a proton beam be subjected to give its protons a wavelength of $1\times {10}^{-10}m$?

• A. 0.0826 volts
• B. 0.0346 volts
• C. 0.0567 volts
• D. 0.0234 volts

Answer 1

The correct option is A 0.0826 volts

$\lambda =\frac{h}{m\nu },KE=\frac{1}{2}m{v}^2\Rightarrow mv=\sqrt{2mKE}$

$KE=qV\Rightarrow \lambda =\frac{h}{\sqrt{2mqV}}\Rightarrow V=\frac{h^2}{{\lambda }^{2}2mq}$

Thus $V=\frac{h^2}{{\left({10}^{-10}\right)}^{2}2mq}=0.0826V$