To what volume one litre of 0.1M acetic acid solution diluted so that the pH of the solution becomes double of the initial ? ( Ka=1.8×10−5)
5.5×105L
Acetic acid is a weak acid.
pH = 12pKa–12 log[conc] = 12×4.7447–12 log(0.1) = 2.3723 + 0.5 = 2.8723
pH of the diluted solution = 2 × 2.8723 = 5.7446
or, 5.7446 = 12pKa–12 log[conc]
or, log[conc] = pKa – 11.4892
= 4.7446 – 11.4892 = - 6.7445 = ¯7.3555
conc. = 1.8×10−7
V1M1=V2M2
1×0.1=V2×1.8×10−7
V2 = 5.5×105L