Question

# To what volume one litre of 0.1M acetic acid solution diluted so that the pH of the solution becomes double of the initial ? ( Ka=1.8×10−5)

A

5.5 x 105L

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B

8 x 104 L

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C

2.4 x 103 L

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D

3.6 x 108 L

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Solution

## The correct option is A 5.5 x 105L Acetic acid is a weak acid. pH = 12pKa–12 log[conc] = 12×4.7447–12 log(0.1) = 2.3723 + 0.5 = 2.8723 pH of the diluted solution = 2 × 2.8723 = 5.7446 or, 5.7446 = 12pKa–12 log[conc] or, log[conc] = pKa – 11.4892 = 4.7446 – 11.4892 = - 6.7445 = ¯7.3555 conc. = 1.8×10−7 V1M1=V2M2 1×0.1=V2×1.8×10−7 V2 = 5.5×105L

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