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Question

Toluene+(KMnO4/KOH) ---->A +( H3O+) ----> C

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Solution

The oxidation of an alkylbenzene in the presence of potassium permanganate/potassium hydroxide leads to the formation of benzoic acid.

This means that toluene reacts with KMnO4 in presence of H+(H3O+) to give
Benzoic acid(C6H5COOH) . Which is compound C.
A is an intermediate formed. Which is an ring with an aldehyde on one C and OK+ group on nearby carbon atom. Which on acidification gives benzoic acid.

I hope this helps :)

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