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Question

Total 5−digits numbers divisible by 6 can be formed using 0, 1, 2, 3, 4, 5 if repetition of digits is not allowed is:

A
60
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B
48
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C
108
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D
216
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Solution

The correct option is C 108
5digits numbers divisible by 6 can be formed using 0, 1, 2, 3, 4, 5
we have to use 1,5 and 2,4 as pairs so, we can put 0,3 as 5th no.
we can put only even digit at last
Taking 0
let 0 be ones place digit
4×3×2×1=24
when last digit not 0
2×3×3×2×1=36
Taking 3
2×4×3×2×1=48
Total=24+36+48=108

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