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Question

Total charge Q is uniformly spread along length of a ring of radius R. A small test charge +q of mass m is kept at the centre of the ring and is given a gentle push along the axis of the ring.
a- Show that the particle executes a simple harmonic oscillations
b- Obtain its time period.

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Solution

(a) Let the charge q is displaced towards the axis of ring.

Electric field at the axis of the ring at a distance z fro the axis of ring is

E=14πε0Qz(R2+Z2)32

Fnet=qE

Fnet=14πε0qQz(R2+Z2)32

zR

Fnet=14πε0qQzR3

Let,K=14πε0qQR3

so,Fnet=Kz

force is directly proportional to the z and directed towards O. so, net force can be written as:

Fnet=Kz

This shows that the particles executes SHM.

(b) ω=Km

T=2πω

T=2πmK

T=2π  m14πε0qQR3

T=2π4πε0mR3Qq


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