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Question

Total charge required for the oxidation of two moles Mn3O4 in to MnO42 in presence of alkaline medium is:

A
5F
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B
10F
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C
20F
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D
None of these
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Solution

The correct option is C 20F
16OH1+Mn3O43MnO42+8H2O+10e
For 1 mol electron required is=10
or 2mol=2×10=20
Charge required=20×F
=20F


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