Total charge required to convert three moles of Mn3O4 to MnO−4 in alkaline medium will be:
A
10F
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B
20F
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C
30F
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D
40F
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Solution
The correct option is C30F (Mn3/+8)3→3Mn6++10e− ∴ 10 Faraday charge is required for conversion of 1 mol of Mn3O4toMnO2−4 so 30 faraday charge is required for 3 mole.