The correct option is D 15
Let cost of eraser be e and cost of pencil be p
As per given statements, we have
15e+25p=185
=>3e+5p=37
=>3e=37−5p --- (1)
Also, 9e+xp=106 --- (2)
From eqns (1),(2), we have
3(37−5p)+xp=106
=>111−15p+xp=106
=>(15−x)p=5 --- (3)
From , we understand that x≠15 as LHS of eqn 3 will be zero but RHS =5.