Question

Total kinetic energy of one mole of an ideal gas at 127${}^o$ $C$ is:

• A. $8.31$ $kJ$
• B. $4.99$ $kJ$
• C. $3.20$ $kJ$
• D. $5.68$ $kJ$

Answer 1

The correct option is B $4.99$ $kJ$

$KE=\frac{3}{2}RT$

$KE=\frac{3\times 8.314\times 400}{2}=4988.4J$ or $4.99kJ$

Hence, the correct answer is option $\text{B}$.