Question

Total no.of degenerate orbital in ${\psi }_{4,2,0}$ orbital of $H$-atom:

• A. one
• B. two
• C. six
• D. five

Answer 1

The correct option is D five

${\psi }_{4,2,0}$ $\to n=4,l=2$ means d - orbitals so, no. of degenerate orbitals = 5 (as d have 5 orbitals).