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Question

Total no. of electrons present in 48 g of Mg2+ are:

A
24NA
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B
2NA
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C
20NA
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D
None of these
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Solution

The correct option is C 20NA
24 gm of magnesium contains NA atoms.
48 gm magnesium contains=2NA atoms
Mg2+ ion contain =122=10 electrons
Hence, 2NA Mg2+ ions will contain =10×2NA=20 NA electrons

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