Question

Total number of arrangements of the letters of the word SUCCESS such that both $C^{\prime }s$ are together and no two $S^{\prime }s$ are together is

• A. $12$
• B. $24$
• C. $96$
• D. $120$

Answer 1

The correct option is B $24$

As $CC$ are together and no two ${}^{\prime }{S}^{\prime }$ are together
$\therefore$ Consider $CC$ as single object. $U,CC,E$ can be arranged in $3!$ ways
$\times U\times CC\times E\times$
Now three ${}^{\prime }{S}^{\prime }$ are to the placed in four available place as ${}^4{c}_3$ ways
$\therefore$ Required number of ways are $3!{\times }^4{C}_3=24$.
Hence choice (b) is correct.