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Question

Total number of atoms in 20g of calcium carbonate _________.

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Solution

Molecular weight of CaCO3 is 100. So, number of moles present in 20g of CaCO3 are 20/100=0.2. Each molecule of CaCO3 has 5 atoms. So, total no. of atoms present are 0.2×5.Na=6.023×1023

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