TOTAL NUMBER OF ATOMS PRESENTIN 34gof NH₃

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Solution

Molar mass of NH₃= 17 g
Number of atoms in 17 g of NH₃ = 6.022 $\times$ 10²³ atoms
Number of atoms in 34 g of NH₃ = $\frac{6.022 \times 10^{23}}{17} \times 34 = 12.043 \times 10^{23} atoms$

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