The correct option is A 3
Electron withdrawing groups (−F, −CN and alkyne) lead to the development of ẟ+ charge on the carbon atom sharing a bond with the electron withdrawing substituents. Electron withdrawing groups pull electron density towards it being more electronegative in nature. Therefore in options (i), (ii) and (iv), −I groups are present.
Electron donating group (−C(CH3)3) leads to the development of ẟ- charge on the carbon atom sharing a bond with the electron donating substituent. Therefore in option (iii), +I group is present.