Question

Total number of divisor of $N=2^5{.3}^4{.5}^{10}{.7}^6$ that are of the form $4n+2,n\ge 1$.

• A. $54$
• B. $55$
• C. $384$
• D. $385$

Answer 1

The correct option is D $385$

$\begin{array}{c}N=2^5{3}^4{5}^{10}{7}^6\\ 4n+2\\ \left(5+1\right)\left(4+1\right)\left(10+1\right)\left(6+1\right)\\ =\frac{2310}{6}=385\end{array}$