Total number of electrons donated by ligands to platinum ion in: $[P t (e n)_{2} {C l}_{2}]$ :

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Solution

The correct option is C 12
The number of electrons donated by two en (ethylenediaammine) is 4 x 2=8 since it is a bidentate ligand
and 2 $C l$ donates 2x2 electrons =4.

So, the total number of electrons donated becomes 8+4=12.

Hence, C is the correct option.

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