Question

Total number of electrons present in 18 ml of water is: (density of water is 1 g mL${}^{-1}$).

• A. $6.02\times {10}^{23}$
• B. $6.02\times {10}^{22}$
• C. $6.02\times {10}^{24}$
• D. $6.02\times {10}^{25}$

Answer 1

Answer: (C)

$6.02\times {10}^{24}$

Solution:

Number electrons present in 1 molecule of $H_{2}O$ is $10$ electrons

Density of water is given i.e. 1 gmL${}^{-1}$

$18mL=18gms$

So number of moles $=\frac{18}{18}=1mol$

So, number of electrons in $18mL{H}_{2}O=10\times 6.023\times {10}^{23}$

So, option C is correct answer i.e. $6.023\times {10}^{24}$