Total number of factors of a number is 24 and the sum of its 3 prime factors out of four, is 25. The product of all 4 prime factors of this number is 1365. Then such a greatest possible number can be
A
17745
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B
28561
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C
4095
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D
can't be determined
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Solution
The correct option is A 17745 Since the Product of 4 prime factors = 1365 =3×5×7×13 and the sum of the 3 prime factors = 25 = (5 + 7 + 13) Now, total number of factors of the required number N = 24 =23×3⇒ (1 + 1)(1 + 1)(1 + 1)(2 + 1) Let N can be expressed as N=3p×5q×7r×13s Thus, in order to N will be greatest possible number in the above expressed form, the power of the greatest prime factors will be greater. So N=3×5×7×132 = 105 × 169 = 17745