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Byju's Answer
Standard VII
Mathematics
Permutation under Restriction
Total number ...
Question
Total number of four digit odd numbers that can be formed by using
0
,
1
,
2
,
3
,
5
,
7
are
A
216
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B
375
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C
400
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D
720
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Solution
The correct option is
D
720
The given digits are
0
,
1
,
2
,
3
,
5
,
7
For thousandth position we have
5
choices.
For tenth and hundredth position we have
6
choices each and for one's position we have
4
choices since the number has to be odd.
So total number of such numbers
=
5
×
6
×
6
×
4
=
720
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0
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