Total number of lines in Lyman series of H spectrum will be (where n = no. of orbits)

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n - 1

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n - 2

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n(n+1)

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Solution

The correct option is B n - 1
Lyman series includes the transition of electron from outer orbit of quantum no. $n$ to 1, where $n > 1$
So no. of lines appeared = $n - 1$

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Total number of lines in Lyman series of H spectrum will be: (where n = no. of orbit)

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