Question

Total number of optically active isomers of $2,3-$dibromobutane will be?

• A. $2$
• B. $3$
• C. $4$
• D. $1$

Answer 1

The correct option is C $4$

There are 2 unsymmetrical carbon atom.

$CH₃{-}^{\ast }CHBr{-}^{\ast }CHBr-CH₃$

Every asymmetrical carbon atom exhibits one leavo and one dextro rotatory isomerisms. As there are two asymmetrical carbon atoms, there are a total of four optical isomersfor 2,3 - dibromobutane

Hence answer is option C