Total number of orbitals in a shell is given by

n³

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3n²

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n²

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n⁴

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Solution

The correct option is C
n²

Total number of orbitals in a shell is given by n².

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Similar questions

n = 4

5 < n_{1} < n_{2} < n_{3} < n_{4}

n_{1} + n_{2} + n_{3} + n_{4} = 35

(n_{1}, n_{2}, n_{3}, n_{4})

n_{1} < n_{2} < n_{3} < n_{4} < n_{5}

n_{1} + n_{2} + n_{3} + n_{4} + n_{5} = 20

(n_{1}, n_{2}, n_{3}, n_{4}, n_{5})

n

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