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Quantum Numbers

Total number ...

Question

Total number of orbitals present in the given stationary state for the principal quantum number having value of $n = 3$ ?

A

9

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B

7

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C

4

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D

6

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Solution

The correct option is A 9
The given principal quantum number n=3
3 shell consists 3s 3p 3d subshell
$3 s - 1$ orbitals
$3 p - 3$ orbitals
$3 d - 5$ orbitals
Totally 9 orbitals in $3^{d}$ shell

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