Question

Total number of pencils required are given by $4x^4+2x^3-2x^2+62x-66$. If each box contains $x^2+2x-3$ pencils, then find the number of boxes to be purchased.

Answer 1

Total number of pencils $=4x^4+2x^3-2x^2+62x-66$

No. of pencils in each box $=x^2+2x-3$

Therefore,

Total no. of boxes $=\frac{\text{Total no. of pencils}}{\text{No. of pencils in each box}}=\frac{4x^4+2x^3-2x^2+62x-66}{x^2+2-3}=4x^2-6x+22$

Hence the total no. of boxes are $(4x^2-6x+22)$.