Total number of points of non-differentiability of f x -3-4 sin x - in - 2 - where - denote the g-i-f areA- 5B- 6C- 9D- 8

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First Principle of Differentiation

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Question

Total number of points of non-differentiability of $f (x) = [3 + 4 s i n x]$ in $[π, 2 π]$ where [.] denote the g.i.f are

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Solution

The correct option is C 8
f(x) = 3 + [4 sinx]
f(x) is non-differentiable where g(x)
=[4sinx] is non differentiable
In $[π, 2 π]$ , g(x) is clearly non-differentiable at 8 points.

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Total number of points of non-differentiability of f(x)=[3+4sinx] in [π,2π] where [.] denote the g.i.f are

The correct option is C 8f(x) = 3 + [4 sinx] f(x) is non-differentiable where g(x) =[4sinx] is non differentiable In [π,2π], g(x) is clearly non-differentiable at 8 points.

Total number of points of non-differentiability of $f (x) = [3 + 4 s i n x]$ in $[π, 2 π]$ where [.] denote the g.i.f are

The correct option is C 8
f(x) = 3 + [4 sinx]
f(x) is non-differentiable where g(x)
=[4sinx] is non differentiable
In $[π, 2 π]$ , g(x) is clearly non-differentiable at 8 points.