Question

Total number of protons in $10$ g of calcium carbonate is :

• A. $4.06\times {10}^{24}$
• B. $3.01\times {10}^{24}$
• C. $3.24\times {10}^{24}$
• D. $2.01\times {10}^{24}$

Answer 1

The correct option is B $3.01\times {10}^{24}$

Correct option is A

$1$ mole of ${\text{CaCO}}_3=20+6+8\times 3=50$ moles of protons.
$100$ g ${\text{CaCO}}_3$ contains $=50$ moles of protons
$10$ g ${\text{CaCO}}_3$ contain $=\frac{50\times 10}{100}$moles of protons
Number of protons $=5\times 6.02\times {10}^{23}$
$=3.01\times {10}^{24}$ protons