Question

Total number of protons in 10 g of calcium carbonate is:

• A. $3.01\times {10}^{24}$
• B. $4.06\times {10}^{24}$
• C. $2.01\times {10}^{24}$
• D. $3.24\times {10}^{24}$

Answer 1

The correct option is A $3.01\times {10}^{24}$

1 mole of $CaC{O}_3=20+6+8\times 3=50$ moles of protons.

100 g $CaC{O}_3$ contain $=50$ moles of protons

10 g $CaC{O}_3$ contain $=\frac{50\times 10}{100}$ moles of protons

Number of protons $=5\times 6.02\times {10}^{23}$

$=3.01\times {10}^{24}$ protons