Total number of radial nodes and angular nodes present in 7p orbitals are:

5 and 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 and 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 and 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7 and 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 5 and 1
Total number of radial nodes = $n - l - 1$
where n = shell number
$l$ = azimuthal quantum number
Total number of nodes = 7 - 1 - 1 = 5
Total number of angular nodes = $l$
So, total angular nodes = 1

Suggest Corrections

Similar questions

3 p

Question 26

Calculate the total number of angular nodes and radical nodes and radical nodes present in 3p orbital.

The difference in number of angular nodes and the number of radial nodes in the orbital to which the last electron of chromium present is ______.

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program