Total number of structural isomers of $C_{4} H_{7} C l$ .

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Solution

There are $7$ isomers of $C_{4} H_{7} C l :$
$∙$ $c i s - 1 - c h l o r o b u t - 1 - e n e$
$∙$ $t r a n s - 1 - c h l o r o b u t - 1 - e n e$
$∙$ $2 - c h l o r o b u t - 1 - e n e$
$∙$ $3 - c h l o r o b u t - 1 - e n e$
$∙$ $1 - c h l o r o b u t - 2 - e n e$
$∙$ $c i s - 2 - c h l o r o b u t - 2 - e n e$
$∙$ $t r a n s - 2 - c h l o r o b u t - 2 - e n e$

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