Total number of terms in the expansion of (1-x-x^2)^5 is ________

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Solution

(1-x-x^2)^5

Now, in the expansion, highest and lowest powers of x will be 10 and 0 respectively.

And since it has continuous powers of x (0,1,2 ....), the expansion will have all the powers of x ranging from 0 to 10.

So the total no of terms will be 11

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