Total number of values in -2 - 2 - and satisfyinglog-cosx-sinx-log-sinx-cosx-2 is

Log_|cosx||sinx|+log_|sinx||cosx|=2 i.e |sinx|=|cosx|≠ 1 and |tanx|=1 ∴ x=±π/4, ± ( π π/4 ), ± ( π+π/4 ), ± ( 2 π π/4 ) i.e 8 values. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trigonometric Equations

Total number ...

Question

Total number of values in $(- 2 π, 2 π)$ and satisfying
$l o g_{| c o s x |} | s i n x | + l o g_{| s i n x |} | c o s x | = 2$ is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

Total number of values in $(- 2 π, 2 π)$ and satisfying
$l o g_{| c o s x |} | s i n x | + l o g_{| s i n x |} | c o s x | = 2$ is

[sin (x - π) + cos (x - \frac{π}{2})] . cos (x - 2 π)

a = c o s x + c o s (x + \frac{2 π}{3}) + c o s (x + \frac{4 π}{3})

b = s i n x + s i n (x + \frac{2 π}{3}) + s i n (x + \frac{4 π}{3})

{log}_{0.5} sin x = 1 - {log}_{0.5} cos x

x ϵ [- 2 π, 2 π]

0 \leq x \leq 2 π

| cos x | \leq sin x

Join BYJU'S Learning Program