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Question

Total number of voids in 0.5 mol of a compound forming hexagonal closed packed structure are

A
6.022×1023
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B
3.011×1023
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C
9.033×1023
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D
4.516×1023
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Solution

The correct option is C 9.033×1023
In hcp, there are 6 atoms per unit cell.
N=6
Number of octahedral voids =N=6
Numer of tetrahedral voids =2N=2×6=12

Total number of voids per unit cell =18
Total number of voids per atom =186=3

Thus, the total no. of voids per mole will be 3×6.023×1023

In 0.5 mol compound,
Total no. of voids =3×0.5×6.023×1023=9.034×1023

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