Total number of words formed by 2 vowels and 3 consonants taken from 4 vowels and 5 consonants is equal to
7200
2 out of 4 vowels can be chosen in 4C2 ways and 3 out of 5 consonants can be chosen in 5C3 ways.
Thus, there are (C2×5C3) groups, each containing 2 vowels and 3 consonants.
Each group contains 5 letters that can be arranged in 5! ways.
∴ Required number of words
(4C2×5C3)×5!=60×120=7200