Total number of words that can be formed using all letters of the word $BRIJESH$ that neither begins with $I$ nor ends with $B$ is equal to.

4920

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3720

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3600

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4800

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Solution

The correct option is B $3720$
Total number of words formed without any restriction $= 7!$

Total number of words beginning with $I = 6!$

Total number of words beginning with $B = 6!$

Total number of words beginning with I and ends with $B = 5!$

Therefore, required number of words $= 7! - 6! - 6! + 5!$

$= 5040 - 2 \times 720 + 120 = 3720$

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