Total numbers of hybrid orbitals present in CH3-C- CH are-

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Idea of Hybridisation

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Question

Total numbers of hybrid orbitals present in $C H_{3} - C \equiv C H$ are:

8

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6

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4

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2

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C H_{3} - C H = C H - C H_{3}

C H_{3} 6 - C H 5 = C H 4 - C H_{2} 3 - C 2 \equiv C H 1

Which hybrid orbitals are used by carbon atoms in the following molecules?

CH₃–CH₃; (b) CH₃–CH=CH₂; (c) CH₃-CH₂-OH; (d) CH₃-CHO (e) CH₃COOH

C H_{3} - C H = C H - C H_{2} - C \equiv C H

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C H_{3} - C H = C H - C \equiv C H

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