Total numbers that can be made using the digits 3,4,5,6,7 and 8 lying between 3000 and 4000, which are divisible by 5 while repetition digits is not allowed is
A
12
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B
24
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C
60
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D
120
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Solution
The correct option is A12 3 must be at thousand’s place and since the number should be divisible by 5, ∴5 must be at unit’s place.
Now, we have to fill two places , ten's and hundred's place which is equal to 4P2=12 ways