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Law of Dominance

Total populat...

Question

Total population of 800 individuals which formed F $_{2}$ population (9 : 3 : 3 : 1) of a cross between yellow round and green wrinkled. Find the number of plants with yellow and wrinkled seeds.

A

150

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B

400

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C

800

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D

300

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Solution

The correct option is A 150
The ratio for the F $_{2}$ population is 9 : 3 : 3 : 1 for round, yellow seeds : round, green seeds : wrinkled, yellow seeds : wrinkled, green seeds.
Therefore, from a population of 800 individuals, the number of plants with yellow and wrinkled seeds are = 3/16 x 800 = 150.
Thus, the correct answer is option A.

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