Total sales of branch $B_{6}$ for both the years is what percent of the total sales of branch $B_{3}$ for both the years?

68.54

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71.11 %

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73.17

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75.55 %

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Solution

The correct option is C $73.17$
Required Percentage
$= [\frac{(70 + 80)}{95 + 110} \times 100] %$
$= (\frac{150}{205} \times 100) %$
$= 73.17 %$

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Total sales of branch B6 for both the years is what percent of the total sales of branch B3 for both the years?

The correct option is C 73.17 Required Percentage =[(70+80)95+110×100]% =(150205×100)%=73.17%

Total sales of branch $B_{6}$ for both the years is what percent of the total sales of branch $B_{3}$ for both the years?

The correct option is C $73.17$
Required Percentage
$= [\frac{(70 + 80)}{95 + 110} \times 100] %$
$= (\frac{150}{205} \times 100) %$
$= 73.17 %$