Total sales of branches $B_{1}, B_{3}, a n d B_{5},$ together for both the years (in thousand numbers) is:

250

No worries! We‘ve got your back. Try BYJU‘S free classes today!

310

No worries! We‘ve got your back. Try BYJU‘S free classes today!

435

No worries! We‘ve got your back. Try BYJU‘S free classes today!

560

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $560$
Total sales of branches $B_{1}, B_{3}, a n d B_{5}$ together for both the years (in thousand numbers)$= (80 + 105) + (95 + 110) + (75 +95) = 560$

Suggest Corrections

Similar questions

Q. Total sales of branches B1, B3 and B5 together for both the years (in thousand numbers) is?

Total sales of branches B1, B3 and B5 together for both the years (in thousands numbers) is:

Directions for the following 5 (Five) items:

Read the following information provided and answer the items that follow. Your answers to these items should be based on the information given only.

I.The bar graph given above shows the sales of books (in thousand number) from six branches of a publishing company during two consecutive years 2000 and 2001.

Sales of Books (in thousand numbers) from Six Branches - B1, B2, B3, B4, B5 and B6 of a publishing Company in 2000 and 2001.

Question 16. Total sales of branches B1, B3 and B5 together for both the years (in thousand numbers) is?

Join BYJU'S Learning Program

Total sales of branches B1,B3,andB5, together for both the years (in thousand numbers) is:

The correct option is D 560Total sales of branches B1,B3,andB5 together for both the years (in thousand numbers)$= (80 + 105) + (95 + 110) + (75 +95) = 560$

Total sales of branches $B_{1}, B_{3}, a n d B_{5},$ together for both the years (in thousand numbers) is:

The correct option is D $560$
Total sales of branches $B_{1}, B_{3}, a n d B_{5}$ together for both the years (in thousand numbers)$= (80 + 105) + (95 + 110) + (75 +95) = 560$