wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Total surface area of a cuboid open at the top having length 2 cm, breadth 3 cm and height 4 cm is .

A
46 cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
48 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
52 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 46 cm2
TSA of a cuboid = 2(lb + bh + lh), where l,b and h are length, breadth and height of a cuboid respectively.
As the cuboid is open at the top. So, we have to subtract the top face area from TSA .
TSA of cuboid open at the top
= 2(lb + bh + lh)lb
=2[(2×3) + (3×4)+(2×4)]2×3
= 46 cm2

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cuboid
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon