Total volume of atoms present in a face-centred cubic unit cell of a metal is: ( $r$ is the atomic radius)

\frac{16}{3} π r^{3}

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\frac{20}{3} π r^{3}

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\frac{24}{3} π r^{3}

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\frac{12}{3} π r^{3}

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Solution

The correct option is A $\frac{16}{3} π r^{3}$
The total number of atoms in FCC is $4$ .

$V = 4 \times \frac{4 π r^{3}}{3} = \frac{16 π r^{3}}{3}$

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Total volume of atoms present in a face-centred cubic unit cell of a metal is: (r is the atomic radius)

The correct option is A 163πr3The total number of atoms in FCC is 4.V=4×4πr33=16πr33

Total volume of atoms present in a face-centred cubic unit cell of a metal is: ( $r$ is the atomic radius)

The correct option is A $\frac{16}{3} π r^{3}$
The total number of atoms in FCC is $4$ .

$V = 4 \times \frac{4 π r^{3}}{3} = \frac{16 π r^{3}}{3}$