Total weight of fruits is 58/3 kg. There are 73/9 kg apple and 19/ 3 kg oranges and remaining pears. Find the weight of pears

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Solution

Dear student,
Given that
$\frac{58}{3} = \frac{73}{9} + \frac{19}{3} + p e a r' s w e i g h t .$
$r e q u i r e d w e i g h t = \frac{58}{3} - \frac{19}{3} - \frac{73}{9}$
$= \frac{39}{3} - \frac{73}{9} = \frac{39 (3) - 73}{9} = \frac{117 - 73}{9} = \frac{44}{9} k g$
Regards

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Total weight of fruits is 58/3 kg. There are 73/9 kg apple and 19/ 3 kg oranges and remaining pears. Find the weight of pears

Dear student, Given that 583 = 739 + 193 + pear's weight. required weight = 583 - 193 - 739 = 393 - 739= 393-739= 117-739= 449kg Regards

Dear student,
Given that
$\frac{58}{3} = \frac{73}{9} + \frac{19}{3} + p e a r' s w e i g h t .$
$r e q u i r e d w e i g h t = \frac{58}{3} - \frac{19}{3} - \frac{73}{9}$
$= \frac{39}{3} - \frac{73}{9} = \frac{39 (3) - 73}{9} = \frac{117 - 73}{9} = \frac{44}{9} k g$
Regards