Question

Tow uniform dice marked 1 to 6 tossed together. The probability of the total 7 in a single throw is

• A. $5/36$
• B. $5/12$
• C. $2/31$
• D. $1/6$.

Answer 1

Answer: (D)

$1/6$.

In a single throw with two dice, 7 can be obtained in the following 6 ways;(6,1),(1,6)(5,2),(2,5),(4,3),(3,4)
total no.of ways = $6^2=36$
The required probability = $\frac{6}{36}=\frac{1}{6}$