Question

Town-A is 65 km due North of Town-B. Town-C is due 44 km due East of Town-B. Calculate the distance from Town-A to Town-C. (Correct to 2 decimal places)

• A. 78.49 km
• B. 79.41 km
• C. 81.49 km
• D. 89.41 km

Answer 1

The correct option is A 78.49 km

The towns A, B and C form a Triangle ΔABC right angled at B.
Town A is North of town B and Town C is East of Town B.
Therefore, AB = 65 km
BC = 44 km
AC is what we need to calculate.
Applying pythagoras theorem in the $\Delta ABC$ we get
$A{B}^2+B{C}^2=A{C}^2$
${65}^2+{44}^2=A{C}^2$
$A{C}^2=6161$
$AC=\sqrt{6161}$
$AC=78.49km$ $\left(Correctto2decimalplaces\right)$