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Question

Trace the following central conics.
x2xy+2y22ax6ay+7a2=0.

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Solution

Trace the conic
x2xy+2y22ax6ay+7a2=0(2xy2a)=±7y2+28ay28aa2+4a2(2xy2a)2=7(y2+4a24ay)+4a2(2xy2a)2+7(y2a)2=4a2

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